Raid "Root of Corrosion"
1 650$
82.5$ will be credited to your accountYou will receive 5% of the order amount to the account balance. Account balance can be used to pay for services on the site in full. You can see your balance in your personal account info (on the top right). Cashback, account balance and operations with it become available after registration on the site.
Raid "Root of Corrosion"
The Root of Corrosion Boost Service is your key to achieving both full and partial raid clears on Normal and Epic difficulties, unlocking access to exceptional loot. In the challenging realm of Tarisland, it takes a daring group of warriors to embark on the formidable 10-player raid. This is precisely why we provide the Root of Corrosion (RoC) raid boost, designed for the bravest adventurers. Securing top-tier gear is crucial in your journey, and raid boss defeats are essential for this. That's where our Root of Corrosion carry service comes into play. If you're looking to bypass the time-consuming process of finding compatible team members and navigating through the demanding raid, look no further. Our expert team is ready to lend you professional support. Opt for our Root of Corrosion boosting service to significantly enhance your character's prowess and stand out in the world of Tarisland.
Root of Corrosion boosting rewards:
- "Root of Corrosion" raid full complition;
- All 4 raid bosses kill: "Ancient Tree", "Merfolc King", "Forest Gemini", "Synthesis Doctor";
- Possible Raid Gear from every boss;
- Possible Raid Token from every boss;
- All materials obtained during the completion.
- Additionally, you may choose any separate bosses.
🕓 ETA: Flexible: 2 days for basic (4d for Elite and 6d for Epic)
🔒 Requirements:
- Character level: 30+ (Normal);
- Gear Score: 90+ (Normal);
- Account share for standard service. Guarantees.
✴️ Please note:
If your character level or gear score isn't sufficient for completing this dungeon, feel free to reach out to us. We will find a character boost service for you and help gear up your character effectively.
💬 Contact with operator if you have any possible questions.
